27x^2-60x-28=0

Solution for 27x^2-60x-28=0 equation:

27x^2-60x-28=0

a = 27; b = -60; c = -28;
Δ = b2-4ac
Δ = -602-4·27·(-28)
Δ = 6624
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{6624}=\sqrt{144*46}=\sqrt{144}*\sqrt{46}=12\sqrt{46}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-60)-12\sqrt{46}}{2*27}=\frac{60-12\sqrt{46}}{54}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-60)+12\sqrt{46}}{2*27}=\frac{60+12\sqrt{46}}{54}
$